A square pyramid has a base with a side length of 6 inches and lateral faces with heights of 11 inches. What is the surface area of the pyra

Question

A square pyramid has a base with a side length of 6 inches and lateral faces with heights of 11 inches. What is the surface area of the pyramid?

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Helga 3 years 2021-07-27T22:19:36+00:00 2 Answers 10 views 0

Answers ( )

  1. thienthanh
    0
    2021-07-27T22:20:56+00:00
    Reply

    Answer:

    SA = 168 in.²

    Step-by-step explanation:

    The surface area is the sum of the area of the base and the areas of the 4 congruent triangular sides.

    s = side of the base

    h = height of each side

    SA = s² + 4(sh/2)

    SA = (6 in.)² + 4(6 in.)(11 in.)/2

    SA = 36 in.² + 132 in.²

    SA = 168 in.²

  2. Ladonna
    0
    2021-07-27T22:21:19+00:00
    Reply

    Answer:

    \huge\boxed{\sf 168\ in.\²}

    Step-by-step explanation:

    Surface area of the base:

    = Length * Length

    = 6 * 6

    = 36 in.²

    Surface Area of 1 Lateral Face:

    = \sf \frac{1}{2} (Base * Height)

    Base = 6 inches

    Height = 11 inches

    = 1/2 (6*11)

    = 3 * 11

    = 33 in.²

    Surface Area of 4 lateral faces:

    = 33 * 4

    = 132 in.²

    Surface Area of the whole pyramid:

    = 132 + 36

    = 168 in.²

    \rule[225]{225}{2}

    Hope this helped!

    ~AH1807

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