A sprinter is running a 100m sprint race. The race begins, and stopwatch is started. The sprinter passes the 12m [N] mark at 1.92 s and pass

Question

A sprinter is running a 100m sprint race. The race begins, and stopwatch is started. The sprinter passes the 12m [N] mark at 1.92 s and passes the 59m [N] mark at 7.98s, What was the sprinter’s average velocity between the two time marks? Show all your work.

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Kim Cúc 3 years 2021-08-07T01:04:16+00:00 1 Answers 42 views 0

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  1. Dau
    0
    2021-08-07T01:05:35+00:00
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    Answer:

    velocity = 7.7558 m/s

    Explanation:

    s = u × t

    s – distance u – velocity t – time

    59 – 12 = (7.98 – 1.92) *u

    47 = ( 6.06) u

    u = 7.7558 m/s

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