A spring with a force constant of 5.0 N/m has a relaxed length of 2.59 m. When a mass is attached to the end of the spring and allowed to co

Question

A spring with a force constant of 5.0 N/m has a relaxed length of 2.59 m. When a mass is attached to the end of the spring and allowed to come to rest, the vertical length of the spring is 3.86 m. Calculate the elastic potential energy stored in the spring. Answer in units of J.

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Verity 3 years 2021-08-21T04:37:02+00:00 1 Answers 5 views 0

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  1. Amity
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    2021-08-21T04:38:51+00:00
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    Answer:

    Explanation:

    Given

    Spring force constant k=5\ N/m

    Relaxed length l_0=2.59\ m

    mass is attached to the end of spring and allowed to come at rest with relaxed length l_2=3.86\ m

    Potential energy stored in the spring

    U=\frac{1}{2}k(\Delta x)^2

    \Delta x=l_2-l_0

    U=\frac{1}{2}\times 5\times (3.86-2.59)^2

    U=4.03\ J

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