A spring of negligible mass and force constant k = 410 N/m is hung vertically, and a 0.200 kg pan is suspended from its lower end. A butcher

Question

A spring of negligible mass and force constant k = 410 N/m is hung vertically, and a 0.200 kg pan is suspended from its lower end. A butcher drops a 2.5 kg steak onto the pan from a height of 0.50 m. The steak makes a totally inelastic collision with the pan and sets the system into vertical SHM

1. What is the speed of the pan and steak immediately after the collision?

2. What is the amplitude of the subsequent motion?

3. What is the period of that motion?

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Khoii Minh 4 years 2021-09-03T12:51:01+00:00 1 Answers 22 views 0

Answers ( )

  1. Xavia
    0
    2021-09-03T12:52:14+00:00
    Reply

    Answer:

    1) 2.9m/s

    2)0.235cm

    3)0.509s

    Explanation:

    1. moments are conserved, when the steak hits the pan:

    velocity ‘v’ of the steak:  

    v = √(2gh) = √(2*9.81*0.5) = 3.13 m/s

    velocity pan + steak is

    v =m_1v_1/(m_1+m_2)= 2.5*3.13/(2.7) = 2.9 m/s

    2.initial kinetic energy of pan + steak = spring energy  

    1/2 mv² = 1/2 kA²  

    where, A = amplitude  

    2.7 x 2.9² = 410 x A²

    A²=22.707/410

    A = 0.235 cm

    3. T = 2π√(m/k) = 2π√(2.7/410) = 0.509 s

    Therefore, the period of that motion is 0.509s

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