A spring has a spring constant of 450 N/m. How much must this spring be stretched to store 49 J of potential energy?

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A spring has a spring constant of 450 N/m. How much must this spring be stretched to store 49 J of potential energy?

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Thu Thủy 1 year 2021-09-01T21:17:27+00:00 1 Answers 5 views 0

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    2021-09-01T21:19:06+00:00

    Answer:

    W = 1/2 K x^2

    x^2 = 2 * W / K = 2 * 49 J / (N/m)  = .218 / m^2

    x =  .467 m

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