A spherical conductor with a 0.193 m radius is initially uncharged. How many electrons should be removed from the sphere in order for it to

Question

A spherical conductor with a 0.193 m radius is initially uncharged. How many electrons should be removed from the sphere in order for it to have an electrical potential of 7.10 kV at the surface?

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Ngọc Khuê 5 months 2021-08-26T19:27:51+00:00 1 Answers 2 views 0

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    2021-08-26T19:29:34+00:00

    Answer:

    The number of electrons removed is  N  = 9.513 *10^{11}

    Explanation:

    From hr question we are told that

        The radius is  r = 0.193 \ m

       The required electrical potential is V  =  7.10 \ kV  =  7.10 *10^{3} V

    The total charge on the sphere  is mathematically evaluated as

               Q = \frac{Vr}{k}

    where k is the coulombs constant with value k =9)*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.

    substituting value

              Q = \frac{7.10 *10^3 * 0.193}{9*10^9}

              Q = 1.522*10^{-7} C

    The number of electron removed is mathematically evaluated as

            N  =  \frac{Q}{e}

    Where e is  the charge on one electron with value e = 1.6 *10^{-19} \ C

      substituting values  

          N  =  \frac{1.522 *10^{-7}}{1.60*10^{-19}}

          N  = 9.513 *10^{11}

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