A solid sphere of radius 42 cm has a total positive charge of 23 µC uniformly distributed throughout its volume. Calculate the magnitude of

Question

A solid sphere of radius 42 cm has a total positive charge of 23 µC uniformly distributed throughout its volume. Calculate the magnitude of the electric field at 150 cm from the center of the sphere.

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Maris 5 years 2021-08-29T09:20:28+00:00 1 Answers 15 views 0

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  1. quangkhai
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    2021-08-29T09:21:48+00:00
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    Answer:

    Electric field due to uniformly charged sphere is 9.2 x 10⁴ N/C

    Explanation:

    Given :

    Radius of the solid sphere, R = 42 cm = 0.42 m

    Total charge on the sphere, Q = 23 μC = 23 x 10⁻⁶ C

    Distance of the point from the center of the sphere, r = 150 cm = 1.5 m

    Since, r > R, so the point is outside the sphere. Thus, the electric field outside the uniformly charged sphere is determine by the relation:

    E=\frac{kQ}{r^{2} }

    Here k is constant and its value is 9 x 10⁹ N·m²/C².

    Substitute the suitable values in the above equation.

    E=\frac{9\times10^{9}\times23\times10^{-6} }{(1.5)^{2} }

    E = 9.2 x 10⁴ N/C

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