A solenoid used to produce magnetic fields for research purposes is 2.1 m long, with an inner radius of 28 cm and 1300 turns of wire. When r

Question

A solenoid used to produce magnetic fields for research purposes is 2.1 m long, with an inner radius of 28 cm and 1300 turns of wire. When running, the solenoid produced a field of 1.3 T in the center. Given this, how large a current does it carry?

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Hồng Cúc 4 years 2021-07-29T03:32:43+00:00 1 Answers 8 views 0

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  1. thienhuong
    0
    2021-07-29T03:33:54+00:00
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    Answer:

    1671 A

    Explanation:

    With a logical assumption that magnetic permeability of vacuum would be used,

    the magnetic field at the centre of a solenoid is given by

    B = μ₀I (N/L)

    Some textbooks use turn density, n = (N/L)

    Either ways,

    B = 1.3 T

    μ₀ = (4π × 10⁻⁷) H/m

    I = ?

    N = 1300 turns

    L = 2.1 m

    I = (BL/μ₀N)

    I = (1.3×2.1) ÷ (4π × 10⁻⁷ × 1300)

    I = 1671 A

    Hope this Helps!!!

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