A softball player is running at 4.88 m/sec when she slides into second base coming to a stop in .872 seconds. How far did she slide, and wha

Question

A softball player is running at 4.88 m/sec when she slides into second base coming to a stop in .872 seconds. How far did she slide, and what was her acceleration?​

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Thu Hương 5 years 2021-09-02T22:24:45+00:00 1 Answers 19 views 0

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  1. thugiang
    0
    2021-09-02T22:25:55+00:00
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    Answer:

    d=v1t – .5at^2

    d=4.88 x .872 – 0.5 x (4.88/0.872) x 0.872^2

    d=4.255 – 2.12

    d= 2.135m

    Explanation:

    acceleration is negative because she is slowing down.

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