A soccer ball is released from rest at the top of a grassy incline. After 8.6 seconds, the ball travels 87 meters and 1.0 s after this, the

Question

A soccer ball is released from rest at the top of a grassy incline. After 8.6 seconds, the ball travels 87 meters and 1.0 s after this, the ball reaches the bottom of the incline. (a) What was the magnitude of the ball’s acceleration, assume it to be constant

in progress 0
Nguyệt Ánh 5 years 2021-08-28T13:44:23+00:00 1 Answers 15 views 0

Answers ( )

  1. minhkhue
    0
    2021-08-28T13:45:27+00:00
    Reply

    Answer:

    a) a = 2.35 m/s^2

    Explanation:

    (a) In order to calculate the magnitude of the acceleration of the ball, you use the following formula, for the position of the ball:

    x=v_ot+\frac{1}{2}at^2     (1)

    x: position of the ball after t seconds = 87 m

    t: time  = 8.6 s

    a: acceleration of the ball = ?

    vo: initial velocity of the ball = 0 m/s

    You solve the equation (1) for a:

    x=0+\frac{1}{2}at^2\\\\a=\frac{2x}{t^2}

    You replace the values of the parameters in the previous equation:

    a=\frac{2(87m)}{(8.6s)^2}=2.35\frac{m}{s^2}

    The acceleration of the ball is 2.35 m/s^2

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )