A small block is attached to an ideal spring and is moving in SHM on a horizontal, frictionless surface. The amplitude of the motion is 0.29

Question

A small block is attached to an ideal spring and is moving in SHM on a horizontal, frictionless surface. The amplitude of the motion is 0.290 m and the period is 3.01 s . Part A What is the acceleration of the block when x

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Latifah 5 years 2021-08-30T00:26:02+00:00 1 Answers 47 views 0

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  1. ngochoa
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    2021-08-30T00:27:02+00:00
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    Answer:

    Explanation:

    ω = 2π/ T = 2π/ 3.01 = 2.087 rad/s

    x(t) = 0.290sin2.087t

    v(t) = 0.290(2.087)cos2.087t

    a(t) = -0.290(2.087²)sin2.087t

    With these three equations, you should be able to plug in what you know to find other values

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