A skater with a mass of 72 kg is traveling east at 5.8 m/s when he collides with another skater of mass 45 kg heading 60° south of west at 1

Question

A skater with a mass of 72 kg is traveling east at 5.8 m/s when he collides with another skater of mass 45 kg heading 60° south of west at 12 m/s. If they stay tangled together, what is their final velocity?

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Adela 2 weeks 2021-09-05T14:24:01+00:00 1 Answers 0 views 0

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    2021-09-05T14:25:12+00:00

    The final velocity is 5.87 m/s

    Explanation:

    Given-

    mass, m_{1} = 72 kg

    speed, v_{1} = 5.8 m/s

    Mass_{2},m_{2}  = 45 kg

    speed_{2},v_{2}  = 12 m/s

    Θ = 60°

    Final velocity, v = ?

    Applying the conservation of momentum:

    m_{1} X v_{1} + m_{2} X v_{2} = (m_{1} +m_{2} ) v

    72 X 5.8 + 45 X 12 X cos 60° = (72 + 45) v

    v = 417.6 + 540 X \frac{0.5}{117}

    v = 417.6 + \frac{270}{117}

    v = 5.87 m/s

    The final velocity is 5.87 m/s

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )