A skater spins at 3rev/s when she stretches her arms outward. If she keeps her fists on her chest she can spin at 4.5rev/s and her body iner

Question

A skater spins at 3rev/s when she stretches her arms outward. If she keeps her fists on her chest she can spin at 4.5rev/s and her body inertia is 3kg.m2. What is her body inertia when she stretches her arms outward?

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Tryphena 5 years 2021-08-13T12:26:54+00:00 1 Answers 11 views 0

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  1. MichaelMet
    0
    2021-08-13T12:28:39+00:00
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    Answer:

    Body inertia I = 4.5 kg/m^2

    Explanation:

    Here, we want to calculate the body inertia when the arms are stretched outwards.

    We know from the question that angular momentum is conserved

    Thus;

    I * 3 = 4.5 * 3

    I = 4.5 kg/m^2

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