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A skateboarder starts at 2.75 m/s and accelerates for 8.90 s over a distance of 16.7 m. What is his final velocity? A) 3.44 m/s<
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Answers ( )
Explanation:
x = 16.7 m
v₀ = 2.75 m/s
t = 8.90 s
Find: v
x = ½ (v + v₀) t
16.7 m = ½ (v + 2.75 m/s) (8.90 s)
v = 1.00 m/s