A scuba diver measures an increase in pressure of around 10^5 Pa upon descending by 10 m, what is the change in force per square centimetre

Question

A scuba diver measures an increase in pressure of around 10^5 Pa upon descending by 10 m, what is the change in force per square centimetre on the diver’s body?

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Gia Bảo 3 years 2021-07-23T09:41:16+00:00 2 Answers 46 views 0

Answers ( )

  1. thienan
    0
    2021-07-23T09:42:17+00:00
    Reply

    Answer:

    ΔP = 10 N / cm^2

    Explanation:

    Solution:-

    – The pressure on an object placed inside any fluid changes linearly with the depth of fluid above the object.

    – A fluid has its density. In our case we will take the density of water:

                                       ρw = 1000 kg/m^3

    – The pressure ( P ) exerted on an object at the depth of ( h ) is given below:

                                      P = ρ*g*h

    Where,

                  g: The gravitational acceleration constant = 9.81 m/s^2

    – The differential expression relating the change in pressure and change in depth of the object under the fluid.

                                       ΔP = ρ*g*Δh

    – We are given that the scuba diver experiences an increase in pressure of:

                                      ΔP = 10^5 N / m^2

    – We are to determine the change in pressure – ( change in force per square centimetre )

    – The conversion of units would be as follows:

                                    ΔP = 10^5 [ N / m^2 ] * [ m^2 / (100cm)^2 ]

                                    ΔP = 100000/10000 [ N / m^2 ] * [ m^2 / cm^2 ]

                                    ΔP = 10 N / cm^2

  2. giabao
    0
    2021-07-23T09:42:58+00:00
    Reply

    Answer:

    Explanation:

    Given that,

    The pressure around the diver is

    P = 10^5 Pa,

    At a height of 10m

    h = 10m

    We want to find the force per square centimeter of the diver body

    Pressure = force / Area

    Force / Area = pressure,

    And since the pressure is given

    Then,

    Force / Area = 10^5 Pa

    Since 1 pascal = 1 N/m²

    Force / Area = 10^5 N/m²

    Since, we know that, 100cm = 1m

    (100cm)² = (1m)²

    10000cm² = 1m²

    10⁴cm² = 1m²

    Then,

    Force / Area = 10^5 N/m² × 1m²/10⁴cm²

    Force / Area = 10 N/cm²

    The required force per unit area is 10 N /cm²

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