a sample of cobalt, A, with a mass of 5.00g, is initially at 25 C. When this sample gains 6.70 J of heat, the temperature rises to 27.9 C. A

Question

a sample of cobalt, A, with a mass of 5.00g, is initially at 25 C. When this sample gains 6.70 J of heat, the temperature rises to 27.9 C. Another sample of cobalt, B, with a mass of 7.00 g, iw initially at 25 C. If sample B gains 5.00 J of heat, what is the final temperature of sample B

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Thiên Di 5 years 2021-07-18T15:40:08+00:00 1 Answers 88 views 0

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  1. thucuc
    0
    2021-07-18T15:42:02+00:00
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    Answer:

    26.5°C

    Explanation:

    We can solve this question using the equation:

    q = m*S*ΔT

    Where Q is heat gained in joules, m is the mass of the sample, S is specific heat and ΔT change in temperature.

    With the sample A we can find specific heat of cobalt in order to find, in sample B, the ΔT and the final temperature:

    Sample A:

    q = m*S*ΔT

    6.70J = 5.00g*S*(27.9°C-25.0°C)

    0.462J/g°C = Specific heat of cobalt

    Sample B:

    q = m*S*ΔT

    5.00J = 7.00g*0.462J/g°C*ΔT

    1.5°C = ΔT

    As the initial temperature of sample B is 25°C, final temperature is:

    25°C + 1.5°C = 26.5°C

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