A rod 14.0 cm long is uniformly charged and has a total charge of – 22.0 μC. Determine the magnitude and direction of the electric field alo

Question

A rod 14.0 cm long is uniformly charged and has a total charge of – 22.0 μC. Determine the magnitude and direction of the electric field along the axis of the rod at a point 36.0 cm from its center.

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Bơ 3 years 2021-08-02T01:46:02+00:00 1 Answers 1816 views 3

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  1. kimchi2
    2
    2021-08-02T01:47:47+00:00
    Reply

    Answer:

    E=1.58*10^6N/C

    The direction is toward the negative x axis i.e the Rod

    Explanation:

    From the question we are told that:

    Length L=14.0cm

    Total charge q=-22.0\muC

    Distance d=36cm=>0.36m

    Generally the equation for Electric Field is mathematically given by

     E=\frac{kq}{d^2}

    Since Magnitude of E is at 36cm away from center

     E=\frac{kq}{d^2-(L/2)^2}

     E=\frac{9*10^9*(22*10^6)}{0.36^2-(0.14m/2)^2}

     E=1.58*10^6N/C

    Therefore with Charge Bearing the Negative sign the direction is toward the negative x axis i.e the Rod

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