A rigid metal tank containing a sample of argon kept at 4.5atm is moved from room temperature (298K) to an oven that raises its temperature

Question

A rigid metal tank containing a sample of argon kept at 4.5atm is moved from room temperature (298K) to an oven that raises its temperature to 377K.

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Delwyn 3 years 2021-08-11T04:42:57+00:00 1 Answers 10 views 0

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  1. Nem
    0
    2021-08-11T04:44:29+00:00
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    Answer:

    5.7 atm

    Explanation:

    The question is missing, but I think it must be about the new pressure of the argon gas.

    Step 1: Given data

    • Initial pressure (P₁): 4.5 atm
    • Initial temperature (T₁): 298 K
    • Final pressure (P₂): ?
    • Final temperature (T₂): 377 K

    Step 2: Calculate the final pressure of the argon gas

    There is a direct relationship between pressure and temperature. Assuming ideal behavior and constant volume (rigid tank), we can calculate the final pressure of the gas using Gay-Lussac’s law.

    P₁/T₁ = P₂/T₂

    P₂ = P₁ × T₂/T₁

    P₂ = 4.5 atm × 377 K/298 K = 5.7 atm

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