A rifle can shoot a 4.2 g bullet at a speed of 965 m/s. If the work on the bullet is done over a distance of 0.75 m, what is the average for

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A rifle can shoot a 4.2 g bullet at a speed of 965 m/s. If the work on the bullet is done over a distance of 0.75 m, what is the average force on the bullet?

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Yến Oanh 1 week 2021-09-05T08:26:56+00:00 1 Answers 0 views 0

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    2021-09-05T08:28:15+00:00

    Answer:

    The average force on the bullet will be “2607.43 N“.

    Explanation:

    The given values are:

    Mass of the bullet,

    m = 4.2 g

    Final speed,

    v = 965 m/s

    Initial speed,

    u = 0

    Distance,

    S = 0.75 m

    According to the Energy theorem,

    ⇒  Work \ done = Change \ in \ kinetic \ energy

    ⇒  F S = (\frac{1}{2} )m(v^2 - u^2)

    On substituting the values, we get

    ⇒  F\times 0.75=0.5\times 0.0042 [(965)^2 - 0]

    ⇒  0.75 F = 0.5\times 0.0042\times 931225

    ⇒  0.75F=1955.57

    ⇒        F=\frac{1955.57}{0.75}

    ⇒            =2607.43 \ N

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