A rectangular loop of wire with width 0.4 cm and length 0.4 cm is oriented with the normal to the face of the loop making an angle of 30° wi

Question

A rectangular loop of wire with width 0.4 cm and length 0.4 cm is oriented with the normal to the face of the loop making an angle of 30° with respect to the direction of B. The B field has a magnitude of 0.77 T. Find the magnetic flux through the loop.

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Thu Thủy 5 years 2021-08-21T04:22:51+00:00 2 Answers 17 views 0

Answers ( )

  1. MichaelMet
    0
    2021-08-21T04:24:26+00:00
    Reply

    Answer:

    1.07×10⁻⁵ Wb

    Explanation:

    Using

    Φ = BAcosθ……………… Equation 1

    Where Φ = magnetic Flux, B = magnetic Field, A = Area of the rectangular loop, Angle between the loop and the Field.

    But

    A = L×W…………………… Equation 2

    Where L = Length, W = Width.

    Substitute equation 2 into equation 1

    Φ = BLWcosΦ……………. Equation 3

    Given: B = 0.77 T, L = 0.4 cm = 0.004 m, W = 0.4 cm = 0.004 m, Ф = 30°

    Substitute into equation 3

    Ф = 0.77(0.004)(0.004)cos30

    Ф  = 1.07×10⁻⁵ Wb.

    Hence the magnetic Field through the loop = 1.07×10⁻⁵ Wb.

  2. bonexptip
    0
    2021-08-21T04:24:35+00:00
    Reply

    Answer:

    0.001067 Wb

    Explanation:

    Parameters given:

    Magnetic field, B = 0.77 T

    Angle, θ = 30º

    Width = 0.4cm = 0.04m

    Length = 0.4cm = 0.04m

    Magnetic flux, Φ(B) is given as:

    Φ(B) = B * A * cosθ

    Where A is Area

    Area = length * width = 0.04 * 0.04 = 0.0016 m²

    Φ(B) = 0.77 * 0.0016 * cos30

    Φ(B) = 0.00167 Wb

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