A reaction at 11.0°C evolves 133.mmol of boron trifluoride gas. Calculate the volume of boron trifluoride gas that is collected. You can ass

Question

A reaction at 11.0°C evolves 133.mmol of boron trifluoride gas. Calculate the volume of boron trifluoride gas that is collected. You can assume the pressure in the room is exactly 1atm . Round your answer to 3 significant digits.

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Khải Quang 3 years 2021-08-21T02:16:52+00:00 1 Answers 59 views 0

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    2021-08-21T02:18:48+00:00

    Answer:

    V=3.10 L

    Explanation:

    Considering the ideal gas equation as:-

    PV=nRT

    where,  

    P is the pressure = 1 atm

    V is the volume = ?

    n is the number of moles = 133 mmol = 0.133 mol

    T is the temperature  

    The conversion of T( °C) to T(K) is shown below:

    T(K) = T( °C) + 273.15  

    So,  

    T = (11.0 + 273.15) K = 284.15 K

    R is Gas constant having value = 0.0821 L.atm/K.mol

    So,  

    V=\frac{nRT}{P}

    Now by putting the values in the above equation

    V=\frac{0.133\times 0.0821\times 284.15}{1}

    V=3.10 L

    Therefore the volume of the gas will be 3.10 L.

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