A ray of laser light strikes a glass surface at an angle a=25.0° tot he normal and it is refracted to an angle b=18.5° to the normal. What i

Question

A ray of laser light strikes a glass surface at an angle a=25.0° tot he normal and it is refracted to an angle b=18.5° to the normal. What is the index of refraction nb for this type of glass? Na=1.00
A. 3.26
B. 3.52
C. 1.32
D. 1.89

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Euphemia 3 years 2021-08-21T21:02:11+00:00 1 Answers 7 views 0

Answers ( )

  1. Acacia
    0
    2021-08-21T21:03:18+00:00
    Reply

    Answer:

    1.33

    Explanation:

    According to snell’s law,

    n = sin(a)/sin(b)

    Given

    a = 25.0°

    b = 18.5°

    Substitute

    n = sin25/sin18.5

    n = 0.4226/0.3173

    n = 1.33

    Hence the index of refraction nb for this type of glass is 1.33

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