A proton moving in the positive x direction with a speed of 8.7 105 m/s experiences zero magnetic force. When it moves in the positive y dir

Question

A proton moving in the positive x direction with a speed of 8.7 105 m/s experiences zero magnetic force. When it moves in the positive y direction it experiences a force of 2.1 10-13 N that points in the positive z direction. Determine the magnitude and direction of the magnetic field.

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Nick 5 years 2021-07-18T15:47:34+00:00 1 Answers 17 views 0

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  1. Euphemia
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    2021-07-18T15:49:29+00:00
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    Answer:

    Explanation:

    The force on a moving charge in a magnetic field acts in a direction perpendicular to the plane containing the magnetic field and the velocity of propagation of charge.

    If charge flows in the direction of magnetic field , or opposite to magnetic field ,no force will act on the charge . Here no force is acting on the moving charge , therefore magnetic field must be along or against the direction of velocity of proton. Hence , magnetic field must be along or againt  positive x direction.

    b = B i or – Bi

    if the proton moves along positive y direction , its velocity can be represented by the formula

    v = 8.7 x 10⁵ j

    Direction of force positive z direction so

    F = 2.1 x 10⁻¹³ k

    F = q ( v x b )

    2.1 x 10⁻¹³ k = 1.6 x 10⁻¹⁹ x (8.7 x 10⁵ j x  B i )

    2.1 x 10⁻¹³ k  = – 13.92  x 10⁻¹⁴k B

    It is not matching so B is not along positive x direction . If it is in – x direction

    b = – Bi

    F = q ( v x b )

    2.1 x 10⁻¹³ k = 1.6 x 10⁻¹⁹ x (8.7 x 10⁵ j x  – B i )

    2.1 x 10⁻¹³ k  =  13.92  x 10⁻¹⁴k B

    B = 1.5 T in negative x direction

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