A pneumatic system is producing 100 lb/in^2 of gauge pressure. A cylinder is needed to press an adhesive label onto a product. It has been d

Question

A pneumatic system is producing 100 lb/in^2 of gauge pressure. A cylinder is needed to press an adhesive label onto a product. It has been determined that 5 lb of force is optimal to complete this task. What is the required diameter of the pneumatic cylinder?

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Yến Oanh 5 years 2021-07-18T15:36:47+00:00 1 Answers 104 views 0

Answers ( )

  1. Farah
    0
    2021-07-18T15:37:56+00:00
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    Answer:

    0.25 in

    Explanation:

    We are given that

    Pressure,P=100lb/in^2

    Force,F=5 lb

    We know that

    P=\frac{F}{A}=\frac{F}{\pi\frac{d^2}{4}}

    Where A=\frac{\pi d^2}{4}

    Substitute the values

    100=\frac{5}{\pi\times \frac{d^2}{4}}

    \frac{d^2}{4}=\frac{5}{100\pi}

    d^2=\frac{5\times 4}{100\pi}

    d=\sqrt{\frac{5\times 4}{100\pi}}

    d=0.25 in

    Hence, the diameter of pneumatic cylinder=0.25 in

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