A plane electromagnetic wave traveling in the positive direction of an x axis in vacuum has components Ex = Ey = 0 and Ez = (4.3 V/m) cos[(π

Question

A plane electromagnetic wave traveling in the positive direction of an x axis in vacuum has components Ex = Ey = 0 and Ez = (4.3 V/m) cos[(π × 1015 s-1)(t – x/c)].(a) What is the amplitude of the magnetic field component?

in progress 0
Tryphena 5 years 2021-09-05T12:42:44+00:00 1 Answers 17 views 0

Answers ( )

  1. thucuc
    0
    2021-09-05T12:44:20+00:00
    Reply

    Answer:

    B_{m}=1.4333*10^{-8}T

    Explanation:

    Given data

    Ex = Ey = 0

    Ez=(4.3V/m)cos(π×10¹⁵s⁻¹)(t-x/c)

    To find

    The amplitude of the magnetic field component

    Solution

    The electric field is given by:

    Ez=(4.3V/m)cos(π×10¹⁵s⁻¹)(t-x/c)

    Where Em=4.3 V/m

    The magnitude of magnetic field is given by:

    B_{m}=\frac{E_{m}}{c}

    Where Em is amplitude of electric field and c is speed of light.

    Substitute the given values

    So

    B_{m}=\frac{4.3V/m}{3.0*10^{8}m/s }\\B_{m}=1.4333*10^{-8}T

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )