A peach pie in a 9.00 in diameter plate is placed upon a rotating tray. Then, the tray is rotated such that the rim of the pie plate moves t

Question

A peach pie in a 9.00 in diameter plate is placed upon a rotating tray. Then, the tray is rotated such that the rim of the pie plate moves through a distance of 208 in. Express the angular distance that the pie plate has moved through in revolutions, radians, and degrees.

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Dâu 5 years 2021-07-18T15:54:35+00:00 1 Answers 36 views 0

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  1. King
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    2021-07-18T15:56:23+00:00
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    Answer:

    a)  X_1=7.36rev

    b)  X_2=46.22radians

    c) X_3=2649.6^o

    Explanation:

    From the question we are told that:

    Diameter d=9.00

    Distance x=208

    Generally the equation for circumference of a circle is mathematically given by

    C=2 \pi r\\\\C=2*\pi*4.5

    C=28.3

    Therefore

    Angular distance that the pie plate has moved through in revolutions is

    X_1=\frac{x}{C}

    X_1=\frac{208}{28.3}

    X_1=7.36rev

    Generally Angular distance that the pie plate has moved through in radians is

    X_2= 7.36rev* 2 \pi

    X_2=46.22radians

    Generally Angular distance that the pie plate has moved through in degrees is

    X_3=7.36rev* 360

    X_3=2649.6^o

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