Share
A particle (q = –4.0 µC, m = 5.0 mg) moves in a uniform magnetic field with a velocity having a magnitude of 2.0 km/s and a direction that i
Question
A particle (q = –4.0 µC, m = 5.0 mg) moves in a uniform magnetic field with a velocity having a magnitude of 2.0 km/s and a direction that is 50° away from that of the magnetic field. The particle is observed to have an acceleration with a magnitude of 5.8 m/s2. What is the magnitude of the magnetic field?
in progress
0
Physics
4 years
2021-07-20T22:43:59+00:00
2021-07-20T22:43:59+00:00 1 Answers
586 views
0
Answers ( )
Answer:
The magnitude of the magnetic field is 4.73 T.
Explanation:
Given that,
Charge of the particle,
It is moving with a velocity of 2 km/s and a direction that is 50° away from that of the magnetic field. The particle is observed to have an acceleration with a magnitude of 5.8 m/s². We need to find the magnitude of magnetic field.
When it enters in magnetic field,
B is magnetic field
So, the magnitude of the magnetic field is 4.73 T.