A parallel plate capacitor consists of two square parallel plates separated by a distance d. the potential across the plates, while keeping

Question

A parallel plate capacitor consists of two square parallel plates separated by a distance d. the potential across the plates, while keeping everything else constant, what happens to the energy stored in the capacitor?
A) There will be % of the energy stored
B) There will be % of the energy stored
C) The energy stored will remain constant
D) The energy stored will double
E) the energy stored will quadruple

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Sapo 5 years 2021-08-06T11:05:23+00:00 1 Answers 25 views 0

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  1. quangkhai
    0
    2021-08-06T11:06:48+00:00
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    Answer:

    E) the energy stored will quadrupled

    Explanation:

    The correct question is

    A parallel plate capacitor consists of two square parallel plates separated by a distance d. If i double the potential across the plates, while keeping everything else constant, what happens to the energy stored in the capacitor?

    A) There will be 1/4 of the energy stored

    B) There will be 1/2 of the energy stored

    C) The energy stored will remain constant

    D) The energy stored will double

    E) the energy stored will quadruple

    The initial energy stored in the capacitor E_{i} = \frac{1}{2}CV^{2}

    where C is the capacitance

    V is the potential difference

    If I double this voltage, while holding every other parameters constant, the new energy stored will be

    E_{n} = \frac{1}{2}C(2V)^{2} = \frac{4}{2}CV^{2}

    E_{n} = 2CV^{2}

    dividing new energy stored by the initial energy stored, we have

    E_{n}/E_{i} = 2CV^{2} ÷ \frac{1}{2}CV^{2} = 4

    the energy stored will be quadrupled.

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