A monochromatic ray of light (f = 5.09 x 1014 Hz) travels from air into medium X. The angle of incidence of the ray in air is 45.0° and the

Question

A monochromatic ray of light (f = 5.09 x 1014 Hz) travels from air into medium X. The angle of incidence of the ray in air is 45.0° and the ray’s angle of refraction in medium X is 29.0°. Calculate the absolute index of refraction of medium X. [Show all work, including the equation and substitution with units.] ​

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Farah 3 years 2021-08-26T11:18:49+00:00 1 Answers 148 views 0

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  1. vankhanh
    0
    2021-08-26T11:20:20+00:00
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    Answer:

    n₂ = 1.459

    Explanation:

    This is a refraction exercise

              n₁ sin θ₁ = n₂ sin θ₂

    where n₁ and n₂ are the refractive indices of the incident and refracted medium, respectively

    In the exercise they indicate that the incident medium is the air that has a refractive index n1 = 1

             n₂ = n₁    \frac{sin \ \theta_1 }{sin\ \theta_2 }

    let’s calculate

            n₂ = 1   \frac{ sin \ 45}{sin \ 29}

            n₂ = 1.459

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