A man weighs 90 N on the surface of earth of radius R at what height above the surface of earth is weight will be 40 N.

Question

A man weighs 90 N on the surface of earth of radius R at what height above the surface of earth is weight will be 40 N.

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Thu Nguyệt 3 years 2021-07-28T11:52:48+00:00 1 Answers 20 views 0

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  1. taiduc
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    2021-07-28T11:54:23+00:00
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    Answer:

    3/2 R

    Explanation:

    Let the Mass of man be m, Mass of earth be M.

    By Newtons, law of gravitation,

    F = GMm/R^2, Where G is gravitational constant

    90 = GMm/R^2

    When man weighs 40N,

    GMm/(New R)^2 = 40

    = 4/9 (90)

    GMm/(New R)^2 = 4/9 (GMm/R^2)

    (New R)^2 = 9/4 R^2

    New R = 3/2 R

    Therefore, height is 3/2 R

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