A man weighing 160 lb stands on the floor of an elevator. What force will be exerted on floor if it (i) descends with a uniform acceleration

Question

A man weighing 160 lb stands on the floor of an elevator. What force will be exerted on floor if it (i) descends with a uniform acceleration of 1 ft/sec 2 (pi) ascends with a uniform acceleration of 1 ft/sec 2

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RobertKer 3 years 2021-07-22T10:50:59+00:00 1 Answers 45 views 0

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  1. Philomena
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    2021-07-22T10:51:59+00:00
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    Answer:

    (a) When elevator descends weight will be 155.026 lb

    (b) When elevator ascends weight will be 164.954 lb    

    Explanation:

    It is given weight of man on the floor of elevator F = 160 lb

    Acceleration due to gravity g=32.17ft/sec^2

    At the floor of elevator weight is equal to W=mg

    So 160=m\times 32.17

    m = 4.973lbsec^2/ft

    (ii) When the elevator descends with uniform acceleration 1ft/sec^2

    Weight will be equal to   W=m(g+a)=4.973\times (32.17+1)=155.026lb

    (ii) When elevator is moving upward

    Weight is equal to W=m(g+a)=4.973\times (32.17+1)=164.954lb

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