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A line is parallel to y = 3x + 5 and intersects the point (-2 , 6). What is the equation of this parallel line?
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A line is parallel to y = 3x + 5 and intersects the point (-2 , 6). What is the equation of this parallel line?
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Mathematics
3 years
2021-08-16T03:53:02+00:00
2021-08-16T03:53:02+00:00 2 Answers
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Answers ( )
Answer:
y = 3x + 12
Step-by-step explanation:
Lines parallel to each other will have the same slope but different y-intercepts. This means that the equation of this parallel line has a slope of 3.
y = 3x + b
Now we need to find the y-intercept by plugging in the point (-2, 6) into the equation. (Replace x with -2 and y with 6.) Then we solve it.
y = 3x + b
6 = 3(-2) + b
6 = -6 + b
+6 +6
12 = b
The y- intercept is 12. So the equation of the parallel line is y = 3x + 12
Answer:
y = 3x + 12
Step-by-step explanation:
Slope of y = 3x + 5 is 3
Line parallel will have same slope 3
Line intersects point at (-2, 6)
Replace into y = mx + b to find
6 = 3(-2) + b
6 = -6 + b
12 = b
Equation of line:
y = 3x + 12