A hydraulic lift is made by sealing an ideal fluid inside a container with an input piston of cross-sectional area 0.004 m2 , and an output

Question

A hydraulic lift is made by sealing an ideal fluid inside a container with an input piston of cross-sectional area 0.004 m2 , and an output piston of cross-sectional area 1.2 m2 . The pistons can slide up or down without friction while keeping the fluid sealed inside. What is the maximum weight that can be lifted when a force of 60 N is applied to the input piston

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Kiệt Gia 3 years 2021-08-31T18:13:19+00:00 1 Answers 16 views 0

Answers ( )

    0
    2021-08-31T18:14:45+00:00

    Answer:

    Maximum weight that can be lifted = 18,000 N

    Explanation:

    Given:

    Cross-sectional area of input (A1) = 0.004 m²

    Cross-sectional area of the output (A2) = 1.2 m
    ²

    Force (F) = 60 N


    Computation:

    Pressure on input piston (P1) = F / A1

    Assume,

    Maximum weight lifted by piston = W

    Pressure on output piston (P2) = W / A2

    We, know that

    P1 = P2

    [F / A1]  = [W / A2]

    [60 / 0.004] = [W / 1.2]

    150,00 = W / 1.2

    Weight = 18,000 N

    Maximum weight that can be lifted = 18,000 N

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