A horizontal, uniform board of weight 125 N and length 4 m is supported by vertical chains at each end. A person weighing 500 N is ha

Question

A horizontal, uniform board of weight 125 N and length 4 m is supported by vertical chains at each end. A person weighing 500 N is hanging from the board. The
tension in the right chain is 250 N.
Which of the following describes where the person is hanging?

in progress 0
Dulcie 5 years 2021-07-31T06:41:35+00:00 1 Answers 1236 views 0

Answers ( )

  1. thienthanh
    1
    2021-07-31T06:42:53+00:00
    Reply

    Answer:

    let Tension in the left chain is F

    here, Fnet = 0

    ⇒F – 500N + 250 N – 125 N = 0

    ⇒F – 375 N = 0

    ⇒F = 375 N

    let r from the left end of the board is the person sitting.

    now torque at left end, τ = 0.

    ⇒375 × (0) – 500N × (r) + 250N × (4m) – 125 N × (2m) = 0

    ⇒0 – 500r + 1000 – 250 = 0

    ⇒750 = 500r

    ⇒r = 750/500 = 1.5 m

    Explanation:

    Can you please give this answer a brainliest answer please

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )