A horizontal conveyer belt moving at 3 ft/s receives sand from a hopper. The sand falls vertically from the hopper to the belt at a speed of

Question

A horizontal conveyer belt moving at 3 ft/s receives sand from a hopper. The sand falls vertically from the hopper to the belt at a speed of 5 ft/s and a flow rate of 500 lbm/s (the density of sand is ~2700 lbm/cubic yard). The conveyor belt isinitially empty but begins to fill with sand. If friction in the drive system and rollers is negligible, find the tension required to pull the belt while the conveyor is filling.

in progress 0
Sigridomena 3 months 2021-09-05T14:21:34+00:00 1 Answers 3 views 0

Answers ( )

    0
    2021-09-05T14:23:24+00:00

    Answer:

    Explanation:

       Force required to pull the conveyor with constant speed

    = rate of change of momentum

    = d( mv )/ dt

    = v dm /dt

    3 x 500

    = 1500 poundal .

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )