A heat engine does 9200 J of work per cycle while absorbing 22.0 kcal of heat from a hightemperature reservoir. What is the efficiency of th

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A heat engine does 9200 J of work per cycle while absorbing 22.0 kcal of heat from a hightemperature reservoir. What is the efficiency of this engine?

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Tryphena 3 years 2021-08-29T05:15:23+00:00 1 Answers 13 views 0

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  1. Orla
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    2021-08-29T05:16:47+00:00
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    Answer: 9.9%

    Explanation: efficiency = (work output /work input) × 100

    Note that, 1 kilocalorie = 4184 joules, hence 22kcal = 22× 4184 = 92048 joules.

    Work output = 9200 j and work input = 92048 j

    Efficiency = (9200/92048) × 100 = 0.099 × 100 = 9.9%

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