A gold wire that is 1.8 mm in diameter and 15 cm long carries a current of 260 mA. How many electrons per second pass a given cross-section

Question

A gold wire that is 1.8 mm in diameter and 15 cm long carries a current of 260 mA. How many electrons per second pass a given cross-section of the wire? (e=1.60×10−19 C) A gold wire that is 1.8 mm in diameter and 15 cm long carries a current of 260 mA. How many electrons per second pass a given cross-section of the wire? ( C) 1.5×1023 1.6×1018 6.3×1015 1.6×1017 3.7×1015

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Khoii Minh 3 years 2021-08-31T07:59:50+00:00 1 Answers 81 views 0

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    2021-08-31T08:01:48+00:00

    Answer:

    (1.6 × 10¹⁸) /s

    Explanation:

    Current flowing in a wire is given by

    I = (Q/t)

    where Q = total charges on the electrons flowing in the wire

    t = time

    But Q = nq

    where n = number of electrons flowing in the wire

    q = charge on one electron = 1.602 × 10⁻¹⁹ C

    So, I = nq/t

    (n/t) = (I/q)

    (n/t) = number of electrons per second, for any cross sectional Area.

    (n/t) = (I/q)

    I = 260 mA = 0.26 A

    q = 1.6 × 10⁻¹⁹ C

    (n/t) = (0.26/(1.602×10⁻¹⁹)) = (1.62 × 10¹⁸) /s = (1.60 × 10¹⁸) /s

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