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A gold wire that is 1.8 mm in diameter and 15 cm long carries a current of 260 mA. How many electrons per second pass a given cross-section
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A gold wire that is 1.8 mm in diameter and 15 cm long carries a current of 260 mA. How many electrons per second pass a given cross-section of the wire? (e=1.60×10−19 C) A gold wire that is 1.8 mm in diameter and 15 cm long carries a current of 260 mA. How many electrons per second pass a given cross-section of the wire? ( C) 1.5×1023 1.6×1018 6.3×1015 1.6×1017 3.7×1015
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Physics
3 years
2021-08-31T07:59:50+00:00
2021-08-31T07:59:50+00:00 1 Answers
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Answer:
(1.6 × 10¹⁸) /s
Explanation:
Current flowing in a wire is given by
I = (Q/t)
where Q = total charges on the electrons flowing in the wire
t = time
But Q = nq
where n = number of electrons flowing in the wire
q = charge on one electron = 1.602 × 10⁻¹⁹ C
So, I = nq/t
(n/t) = (I/q)
(n/t) = number of electrons per second, for any cross sectional Area.
(n/t) = (I/q)
I = 260 mA = 0.26 A
q = 1.6 × 10⁻¹⁹ C
(n/t) = (0.26/(1.602×10⁻¹⁹)) = (1.62 × 10¹⁸) /s = (1.60 × 10¹⁸) /s