A generator rotates at 95 Hz in a magnetic field of 0.025 T. It has 550 turns and produces an rms voltage of 170 V and an rms current of 60.

Question

A generator rotates at 95 Hz in a magnetic field of 0.025 T. It has 550 turns and produces an rms voltage of 170 V and an rms current of 60.0 A.

Required:
a. What is the peak current produced?
b. What is the area of each turn of the coil?

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Jezebel 3 years 2021-08-14T18:01:14+00:00 1 Answers 8 views 0

Answers ( )

    0
    2021-08-14T18:02:20+00:00

    Answer:

    Peak current= 84.86 A

    Area of each turn = 0.029 m^2

    Explanation:

    The peak value of current can be obtained from Irms= 0.707Io. Where Io is the peak current.

    Hence;

    Irms= 60.0A

    Io= Irms/0.707

    Io = 60.0/0.707

    Io= 84.86 A

    Vrms= 0.707Vo

    Vo= Vrms/0.707= 170/0.707 = 240.45 V

    From;

    V0 = NABω

    Where;

    Vo= peak voltage

    N= number of turns

    B= magnetic field

    A= area of each coil

    ω= angular velocity

    But ω= 2πf = 2×π×95= 596.9 rads-1

    Substituting values;

    A= Vo/NBω

    A= 240.45/550×0.025×596.9

    A= 0.029 m^2

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