A gas at 1.8 atm, 140 K, and 4.5 L is adjusted to standard temperature and pressure conditions. What is the new volume?

Question

A gas at 1.8 atm, 140 K, and 4.5 L is adjusted to standard temperature and
pressure conditions. What is the new volume?

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Thu Thảo 5 years 2021-08-11T23:30:32+00:00 1 Answers 12 views 0

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    2021-08-11T23:32:03+00:00
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    From the equation, \frac{p1 * v1}{t1} = \frac{p2 * v2}{t2}, we make v2 the subject of the formula, so that gives us: \frac{p1 * v1 * t2}{p2 * t1}

    Standard temperature = 273k

    Standard pressure = 1atm

    Plugging in our values, \frac{1.8 * 4.5 * 273}{1 * 140} = \frac{2211.3}{140} = 15.795 litres

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