## A flat loop of wire consisting of a single turn of cross-sectional area 8.80 cm^2 is perpendicular to a magnetic field that increases unifor

Question

A flat loop of wire consisting of a single turn of cross-sectional area 8.80 cm^2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 2.80 T in 1.01 s.
a. What is the resulting induced current if the loop has a resistance of 1.00Î©?

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3 years 2021-08-09T14:41:31+00:00 1 Answers 14 views 0

0.00122 A

Explanation:

Parameters given:

Area, A = 8.8 cm² = 0

00088 m²

Initial Magnetic field, Bin = 0.5 T

Final magnetic field, Bfin = 2.8

Time taken, t = 1.01 s

Resistance, R = 1 ohms

EMF induced in a loop of wire of cross sectional area, A due to a changing magnetic field is:

EMF = [-(Bfin – Bin) * N * A] / t

Where N = number of loops = 1

EMF = [-(2.8 – 0.5) * 1 * 0.00088] / 1.01

EMF = -0.00122 V

We know that

V = I * R

Hence, current, I, will be:

I = V/R

I = 0.00122/1 = 0.00122 A