A field is a rectangle with a perimeter of 1100 feet. The length is 300 feet more than the width. Find the width and length of the rectangul

Question

A field is a rectangle with a perimeter of 1100 feet. The length is 300 feet more than the width. Find the width and length of the rectangular field

in progress 0
Vân Khánh 5 years 2021-09-05T12:17:38+00:00 2 Answers 35 views 0

Answers ( )

  1. thanhha
    0
    2021-09-05T12:19:14+00:00
    Reply

    Answer:

    The rectangular field is 425 feet by 125 feet.

    Step-by-step explanation:

    Let w represent the width of the rectangular field.

    Since the length is 300 feet more than the width, the length can be modeled by the expression (w + 300).

    The perimeter of a rectangle is given by the formula:

    P=2(w+\ell)

    Where P is the perimeter and w and l are the width and length, respectively.

    We are given that the perimeter is 1,100 feet. Substitute:

    1100=2(w+\ell)

    Divide both sides by two:

    550=w+\ell

    We know that l = (w + 300). So:

    550=w+(w+300)

    Simplify:

    2w=250

    Divide both sides by two. So, the width is:

    w=125\text{ feet}

    Since the length is 300 feet more than the width, that means the length is 425 feet.

    The rectangular field is 425 feet by 125 feet.

  2. Amity
    0
    2021-09-05T12:19:17+00:00
    Reply

    Answer:

    Step-by-step explanation:

    perimeter of rectangle = 1100

    let breadth be x

    length = 300 + x

    perimeter of rectangle = 2(l + b)

    1100 = 2(300 + x + x)

    1100 = 2(300 + 2x)

    1100 = 600 + 4x

    1100 – 600 = 4x

    500 = 4x

    500/4 = x

    125 = x

    therefore breadth is 125 feet

    length = 300 + 125

    =425 feet

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )