A compressed gas cylinder is filled with 5270 g of argon gas. The pressure inside the cylinder is 2050 psi at a temperature of 18C. The valv

Question

A compressed gas cylinder is filled with 5270 g of argon gas. The pressure inside the cylinder is 2050 psi at a temperature of 18C. The valve to the cylinder is opened and gas escapes until the pressure inside the cylinder is 650. psi and the temperature is 26 C. How many grams of argon remain in the cylinder

in progress 0
Helga 3 years 2021-07-23T13:01:59+00:00 1 Answers 14 views 0

Answers ( )

  1. Amity
    0
    2021-07-23T13:03:39+00:00
    Reply

    Answer:

    A compressed gas cylinder is filled with 5270 g of argon gas.

    The pressure inside the cylinder is 2050 psi at a temperature of 18C.

    The valve to the cylinder is opened and gas escapes until the pressure inside the cylinder is 650. psi and the temperature are 26 C.

    How many grams of argon remains in the cylinder?

    Explanation:

    First, calculate the volume of argon gas that is present in the gas cylinder by using the ideal gas equation:

    Mass of Ar gas is — 5270g.

    The number of moles of Ar gas:

    Number of moles of Ar gas=\frac{given mass of Ar}{its atomic mass} \\ =\frac{5270g}{39.948g/mol} \\ =131.9mol

    Temperature T=(18+273)K=291K

    Pressure P=2050psi

    2050* 0.0680atm\\\\=139.4atm\\

    Volume V=?

    PV=nRT\\139.4atm * V=131.9mol *0.0821L.atm.mol-1.K-1 * 291K\\=>V=\frac{131.9mol *0.0821L.atm.mol-1.K-1 * 291K}{139.4atm} \\=>V=22.6L

    Using this volume V=22.6L

    Pressure=650psi=44.2atm

    Temperature T= (26+273)K=299K

    calculate number of moles “n” value:

    PV=nRT\\=>n=\frac{PV}{RT} \\=>n=\frac{44.2atm*22.6L}{0.0821L.atm.mol^-1K^-1* 299K} \\=>n=40.7mol

    Mass of 40.7mol of Ar gas:

    mass of Ar gas=number of moles * its atomic mass\\\\ =40.7mol* 39.948g/mol\\\\ =1625.8g

    Answer:

    The mass of Ar gas becomes 1625.8g.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )