A compound composed of only nitrogen and iodine is found to contain 3.55% nitrogen by mass. Its empirical and molecular formulas are the sam

Question

A compound composed of only nitrogen and iodine is found to contain 3.55% nitrogen by mass. Its empirical and molecular formulas are the same. What is the hybridization of the nitrogen atom in this compound?

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Lệ Thu 5 years 2021-07-13T09:27:14+00:00 1 Answers 15 views 0

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  1. Philomena
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    2021-07-13T09:28:16+00:00
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    Answer:

    The nitrogen atom is sp³ hybridized

    This is trigonal pyrymid shape

    Explanation:

    Step 1: Data given

    A compound contains only nitroen (N) and Iodine (I)

    The procent of nitrogen by mass = 3.55%

    Atomic mass of N = 14.0 g/mol

    Atomic mass of I = 126.9 g/mol

    Step 2: Calculate mass % of iodine

    Mass % iodine = 100 % – 3.55%

    Mass % iodine = 96.45 %

    Step 3: Calculate number of moles

    Let’s suppose the total mass = 100 grams

    Mass of N = 3.55 grams

    Mass of I = 96.45 grams

    Moles N = 3.55 grams / 14.0 g/mol = 0.254 moles

    Moles I = 96.45 grams / 126.9 g/mol = 0.760 moles

    Step 4: Calculate empirical formula

    For 0.254 moles N we have 0.760 moles I this is 1:3

    This means that for 1 mol N we have 3 moles I

    The empirical ( and also the molecular) formula is I3N

    The nitrogen atom is sp³ hybridized.

    This is trigonal pyrymid shape

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