A community plans to build a facility to convert solar radiation to electrical power. The community requires 2.20 MW of power, and the syste

Question

A community plans to build a facility to convert solar radiation to electrical power. The community requires 2.20 MW of power, and the system to be installed has an efficiency of 30.0% (that is, 30.0% of the solar energy incident on the surface is converted to useful energy that can power the community). Assuming sunlight has a constant intensity of 1 020 W/m2, what must be the effective area of a perfectly absorbing surface used in such an installation

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Ngọc Diệp 4 years 2021-08-17T02:54:15+00:00 1 Answers 16 views 0

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  1. thnahdat
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    2021-08-17T02:55:18+00:00
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    Answer:

    The answer is “\bold{7.18 \times 10^3 \ m^2}“.

    Explanation:


    The efficiency system:

    \eta =\frac{P_{req}}{P} \times 10\\\\P =\frac{P_{req}}{\eta} \times 10\\\\

       =(\frac{2.20 \times 10^6 \ W}{30})\times 100\\\\=(\frac{220 \times 10^6 \ W}{30})\\\\=(\frac{22 \times 10^6 \ W}{3})\\\\=7.33 \times 10^6 \ W  

    Using formula:

    A=\frac{P}{I}

    Effective area:

    A= \frac{7.33 \times 10^6 \ W}{1020\ \frac{W}{m^2}}\\\\

       =\frac{7.33 \times 10^6 }{1020}\ m^2 \\\\ =0.0071862 \times 10^6 \ m^2 \\\\=7.1862 \times 10^3 \ m^2 \\\\  

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