A coil spring stretches by 2.50 cm when a mass of 750 g is suspended from it. (a) Find the force constant of the spring. (b) How much will t

Question

A coil spring stretches by 2.50 cm when a mass of 750 g is suspended from it. (a) Find the force constant of the spring. (b) How much will the spring stretch if 800 g is suspended from it

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Verity 3 years 2021-08-19T18:30:31+00:00 1 Answers 2 views 0

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    2021-08-19T18:31:57+00:00

    Answer:

    (a) 294 N/m

    (b) 0.027 m or 2.7 cm

    Explanation:

    (a) From Hook’s law,

    F = ke……………………. Equation 1.

    make k the subject of the equation

    k = F/e………………… Equation 2

    Where F = force applied on the spring, k = spring constant, e = extension.

    From the question, the force applied to the spring is the weight of the mass.

    F = mg = 0.75(9.8) = 7.35 N

    Also, e = 2.5 cm = 0.025 m

    Substitute these values into equation 2

    k = 7.35/0.025

    k = 294 N/m.

    (b) If a mass of 800 g is suspended,

    F = ke

    e = F/k………………. Equation 3

    F = mg = 0.8(9.8) = 7.84 N,

    k = 294 N/m.

    Substitute these values into equation 3

    e = 7.84/294

    e = 0.027 m

    e = 2.7 cm

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