A cog system on the beginning segment of a roller coaster needs to get 29 occupied cars up a 120-m vertical rise over a time interval of 60

Question

A cog system on the beginning segment of a roller coaster needs to get 29 occupied cars up a 120-m vertical rise over a time interval of 60 s. Each car experiences a gravitational force of 5900 N. The cars start at rest and end up moving at 0.50 m/s.

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King 3 years 2021-08-31T03:07:43+00:00 1 Answers 0 views 0

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    2021-08-31T03:08:44+00:00

    Answer:

    Hello your question has some missing part attached below is the missing part

    How much work is done by the cog system on the cars?

    answer : 2.053 * 10^7 J

    Explanation:

    Total weight of car ( wT )  = 5900 * 29 = 171100 N

    mass of car ( mT ) = wT / g  = 171100 / 9.81 = 17459.18 kg

    Hence work done by the cog system on the cars

    W = ( KE_{2} + PE_{2} ) – ( KE_{1} + PE_{1} )

        = ( 1/2 mv^2 + mgh ) – ( 0 )

        = ( 1/2 * 17459.18 * 0.50^2) + ( 17459.18 * 9.81 * 120 )

        = 2.053 * 10^7 J

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