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A cog system on the beginning segment of a roller coaster needs to get 29 occupied cars up a 120-m vertical rise over a time interval of 60
Question
A cog system on the beginning segment of a roller coaster needs to get 29 occupied cars up a 120-m vertical rise over a time interval of 60 s. Each car experiences a gravitational force of 5900 N. The cars start at rest and end up moving at 0.50 m/s.
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Physics
3 years
2021-08-31T03:07:43+00:00
2021-08-31T03:07:43+00:00 1 Answers
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Answers ( )
Answer:
Hello your question has some missing part attached below is the missing part
How much work is done by the cog system on the cars?
answer : 2.053 * 10^7 J
Explanation:
Total weight of car ( wT ) = 5900 * 29 = 171100 N
mass of car ( mT ) = wT / g = 171100 / 9.81 = 17459.18 kg
Hence work done by the cog system on the cars
W = ( KE
+ PE
) – ( KE
+ PE
)
= ( 1/2 mv^2 + mgh ) – ( 0 )
= ( 1/2 * 17459.18 * 0.50^2) + ( 17459.18 * 9.81 * 120 )
= 2.053 * 10^7 J