A circle is centered at the point (5,-4) and passes through the point (-3, 2). what is the equation of this circle?

Question

A circle is centered at the point (5,-4) and passes through the point (-3, 2). what is the equation of this circle?

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Ladonna 4 years 2021-07-28T01:47:07+00:00 1 Answers 9 views 0

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  1. ngocdiep
    0
    2021-07-28T01:48:25+00:00
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    Answer:

    (x-5)² + (y+4)² = 100

    Step-by-step explanation:

    The formula for calculating the equation of a circle is expressed as;

    (x-a)² + (y-b)² = r² where:

    (a,b) is the centre of the circle

    r is the radius

    Get the radius using the distance formula;

    r = √(2-(-4))²+(-3-5)²

    r = √6²+(-8)²

    r = √36+64

    r =√100

    r² = 100

    Since a = 5 and b = -4, on substituting into the formula;

    (x-5)² + (y+4)² = 100

    This gives the required equation

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )