A chemist makes of nickel(II) chloride working solution by adding distilled water to of a stock solution of nickel(II) chloride in water.Cal

Question

A chemist makes of nickel(II) chloride working solution by adding distilled water to of a stock solution of nickel(II) chloride in water.Calculate the concentration of the chemist’s working solution. Round your answer to significant digits.

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Amity 6 months 2021-07-11T05:49:49+00:00 1 Answers 2 views 0

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    2021-07-11T05:51:29+00:00

    Answer:

    0.0900 mol/L

    Explanation:

    A chemist makes 330. mL of nickel(II) chloride working solution by adding distilled water to 220. mL of a 0.135 mol/L stock solution of nickel(II) chloride in water. Calculate the concentration of the chemist’s working solution. Round your answer to significant digits.

    Step 1: Given data

    • Initial concentration (C₁): 0.135 mol/L
    • Initial volume (V₁): 220. mL
    • Final concentration (C₂): ?
    • Final volume (V₂): 330. mL

    Step 2: Calculate the concentration of the final solution

    We prepare a dilute solution from a concentrated one. We can calculate the concentration of the working solution using the dilution rule.

    C₁ × V₁ = C₂ × V₂

    C₂ = C₁ × V₁/V₂

    C₂ = 0.135 mol/L × 220. mL/330. mL = 0.0900 mol/L

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