A charged particle moving through a magnetic field at right angles to the field with a speed of 24.7 m/s experiences a magnetic force of 2.3

Question

A charged particle moving through a magnetic field at right angles to the field with a speed of 24.7 m/s experiences a magnetic force of 2.38 10-4 N. Determine the magnetic force on an identical particle when it travels through the same magnetic field with a speed of 5.64 m/s at an angle of 21.2° relative to the magnetic field. N

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Thiên Di 5 years 2021-08-22T03:44:10+00:00 1 Answers 23 views 0

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  1. minhkhoi
    0
    2021-08-22T03:45:30+00:00
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    Answer:

    Explanation:

    let the charge is q. velocity, v = 24.7 m/s

    magnetic force, F = 2.38 x 10^-4 N

    Let the magnetic field is B.

    Velocity, v’ = 5.64 m/s

    angle, θ = 21.2°

    The force experienced by a charged particle placed in a magnetic field is given by

    F = q x v x B x Sinθ

    in first case

    2.38 x 10^-4 = q x 24.7 x B x Sin 90 …. (1)

    in second case

    F = q x 5.64 x B x Sin 21.2°      …. (2)

    Divide equation (2) by equation (1), we get

    \frac{F}{2.38\times 10^{-4}}=\frac{5.64\times Sin 21.2}{24.7\times Sin 90}

    F = 1.97 x 10^-5 N

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