A charge of 0.05 C moves a negative charge upward due to a 2 N force exerted by an electric field. What is the magnitude and direction

Question

A charge of 0.05 C moves a negative charge upward due to a 2 N force exerted by an electric field. What is the
magnitude and direction of the electric field?
0.03 N upward
0.03 N downward
40 N upward
40 N downward

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Maris 5 years 2021-08-03T06:01:39+00:00 2 Answers 25 views 0

Answers ( )

  1. Calantha
    0
    2021-08-03T06:02:41+00:00
    Reply

    Answer:

    Electric field at this position of charge is 40 N/C and upwards in the direction of force

    Explanation:

    As we know that the force on a charge due to electric field is given as

    F = qE

    here we know that

    F = 2 N

    q = 0.05 C

    now from above formula

    2 = (0.05) E

    here we have

    E = 40 N/C

  2. Gerda
    0
    2021-08-03T06:03:32+00:00
    Reply

    Answer:

    40 n/c downward on edge! 🙂

    Explanation:

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